Re: [IRCA] 1130 - interference reported by CKWX

["HASCALL, DAVID CIV DFAS" <DAVID.HASCALL@xxxxxxxx>]

Thanks Deanne.  Inquiring minds want to know (maybe just me, hi), how
can you figure ERP from power (25 Kw) and the numbers from the plot
info?  That'd be good info to know (i.e. I know that my local WNDE 1260
is stronger at night and want to know what the ERP is versus the actual
5 Kw, transmitted).

73,
Dave



------------------------------

Message: 2
Date: Wed, 29 Sep 2010 13:31:38 -0600
From: Deane McIntyre <dmcintyr@xxxxxxxxxxx>
To: Mailing list for the International Radio Club of America
	<irca@xxxxxxxxxxxxxxxx>
Subject: Re: [IRCA] 1130 - interference reported by CKWX
Message-ID: <C79FAAE8-5911-4F9D-8596-77A033B5CA17@xxxxxxxxxxx>
Content-Type: text/plain; charset=us-ascii


On 2010-09-29, at 1:20 PM, HASCALL, DAVID CIV DFAS wrote:

> I do not know how to figure out effective radiated power but I could
see
> where 25Kw., directly NE of the station, would sound like 50 Kw., or
> better.
> 
>
http://www.fcc.gov/ftp/Bureaus/MB/Databases/AM_DA_patterns/1355584-11043
> 2.pdf
> 


You are correct - effective radiated power works out to 81.6 kW
at an azimuth of 45 degrees (and 51.2 kW straight north)

73,

Deane McIntyre VE6BPO

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